Search a number
-
+
1252433125213 is a prime number
BaseRepresentation
bin10010001110011010110…
…101001101111101011101
311102201202012212211220221
4102032122311031331131
5131004440340001323
62355205420241341
7156325313625214
oct22163265157535
94381665784827
101252433125213
11443176937126
121828913a0251
139114747099a
144489205c07b
15228a2e9b55d
hex1239ad4df5d

1252433125213 has 2 divisors, whose sum is σ = 1252433125214. Its totient is φ = 1252433125212.

The previous prime is 1252433125067. The next prime is 1252433125217. The reversal of 1252433125213 is 3125213342521.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1252335570084 + 97555129 = 1119078^2 + 9877^2 .

It is an emirp because it is prime and its reverse (3125213342521) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1252433125213 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1252433125217) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 626216562606 + 626216562607.

It is an arithmetic number, because the mean of its divisors is an integer number (626216562607).

Almost surely, 21252433125213 is an apocalyptic number.

It is an amenable number.

1252433125213 is a deficient number, since it is larger than the sum of its proper divisors (1).

1252433125213 is an equidigital number, since it uses as much as digits as its factorization.

1252433125213 is an evil number, because the sum of its binary digits is even.

The product of its digits is 43200, while the sum is 34.

Adding to 1252433125213 its reverse (3125213342521), we get a palindrome (4377646467734).

The spelling of 1252433125213 in words is "one trillion, two hundred fifty-two billion, four hundred thirty-three million, one hundred twenty-five thousand, two hundred thirteen".