Base | Representation |
---|---|
bin | 10010001110100001110… |
… | …100110000000110110101 |
3 | 11102202001101122020021122 |
4 | 102032201310300012311 |
5 | 131010210403142240 |
6 | 2355225210553325 |
7 | 156331240046660 |
oct | 22164164600665 |
9 | 4382041566248 |
10 | 1252550443445 |
11 | 443227087044 |
12 | 182904738845 |
13 | 91165869062 |
14 | 448a387a6d7 |
15 | 228ad4224b5 |
hex | 123a1d301b5 |
1252550443445 has 32 divisors (see below), whose sum is σ = 1754672467968. Its totient is φ = 840454325568.
The previous prime is 1252550443427. The next prime is 1252550443453. The reversal of 1252550443445 is 5443440552521.
It is a cyclic number.
It is not a de Polignac number, because 1252550443445 - 28 = 1252550443189 is a prime.
It is a super-2 number, since 2×12525504434452 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1252550443396 and 1252550443405.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 8724614 + ... + 8867016.
It is an arithmetic number, because the mean of its divisors is an integer number (54833514624).
Almost surely, 21252550443445 is an apocalyptic number.
It is an amenable number.
1252550443445 is a deficient number, since it is larger than the sum of its proper divisors (502122024523).
1252550443445 is a wasteful number, since it uses less digits than its factorization.
1252550443445 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 147809.
The product of its (nonzero) digits is 1920000, while the sum is 44.
Adding to 1252550443445 its reverse (5443440552521), we get a palindrome (6695990995966).
The spelling of 1252550443445 in words is "one trillion, two hundred fifty-two billion, five hundred fifty million, four hundred forty-three thousand, four hundred forty-five".
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