Search a number
-
+
1252553400151 is a prime number
BaseRepresentation
bin10010001110100010000…
…000000001111101010111
311102202001121012110010021
4102032202000001331113
5131010212132301101
62355225354210011
7156331304143054
oct22164200017527
94382047173107
101252553400151
114432288164a9
12182905723907
1391166362aa1
14448a400a02b
15228ad8085a1
hex123a2001f57

1252553400151 has 2 divisors, whose sum is σ = 1252553400152. Its totient is φ = 1252553400150.

The previous prime is 1252553400083. The next prime is 1252553400167. The reversal of 1252553400151 is 1510043552521.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1252553400151 - 29 = 1252553399639 is a prime.

It is a super-2 number, since 2×12525534001512 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1252553400181) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 626276700075 + 626276700076.

It is an arithmetic number, because the mean of its divisors is an integer number (626276700076).

Almost surely, 21252553400151 is an apocalyptic number.

1252553400151 is a deficient number, since it is larger than the sum of its proper divisors (1).

1252553400151 is an equidigital number, since it uses as much as digits as its factorization.

1252553400151 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 30000, while the sum is 34.

Adding to 1252553400151 its reverse (1510043552521), we get a palindrome (2762596952672).

The spelling of 1252553400151 in words is "one trillion, two hundred fifty-two billion, five hundred fifty-three million, four hundred thousand, one hundred fifty-one".