Search a number
-
+
1252661356853 is a prime number
BaseRepresentation
bin10010001110101000011…
…011110110100100110101
311102202100010100012212122
4102032220123312210311
5131010422301404403
62355244212125325
7156334054564454
oct22165033664465
94382303305778
101252661356853
11443283751a15
12182935906845
13911828310aa
14448b44acb9b
15228b8030838
hex123a86f6935

1252661356853 has 2 divisors, whose sum is σ = 1252661356854. Its totient is φ = 1252661356852.

The previous prime is 1252661356847. The next prime is 1252661356883. The reversal of 1252661356853 is 3586531662521.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1193038461169 + 59622895684 = 1092263^2 + 244178^2 .

It is an emirp because it is prime and its reverse (3586531662521) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1252661356853 - 212 = 1252661352757 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1252661356795 and 1252661356804.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1252661356813) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 626330678426 + 626330678427.

It is an arithmetic number, because the mean of its divisors is an integer number (626330678427).

Almost surely, 21252661356853 is an apocalyptic number.

It is an amenable number.

1252661356853 is a deficient number, since it is larger than the sum of its proper divisors (1).

1252661356853 is an equidigital number, since it uses as much as digits as its factorization.

1252661356853 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 7776000, while the sum is 53.

The spelling of 1252661356853 in words is "one trillion, two hundred fifty-two billion, six hundred sixty-one million, three hundred fifty-six thousand, eight hundred fifty-three".