12529149472067 has 2 divisors, whose sum is σ = 12529149472068. Its totient is φ = 12529149472066.

The previous prime is 12529149471977. The next prime is 12529149472069. The reversal of 12529149472067 is 76027494192521.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 12529149472067 - 2⁴⁰ = 11429637844291 is a prime.

Together with 12529149472069, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 12529149471997 and 12529149472015.

It is not a weakly prime, because it can be changed into another prime (12529149472069) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6264574736033 + 6264574736034.

It is an arithmetic number, because the mean of its divisors is an integer number (6264574736034).

Almost surely, 2^{12529149472067} is an apocalyptic number.

12529149472067 is a deficient number, since it is larger than the sum of its proper divisors (1).

12529149472067 is an equidigital number, since it uses as much as digits as its factorization.

12529149472067 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 15240960, while the sum is 59.

The spelling of 12529149472067 in words is "twelve trillion, five hundred twenty-nine billion, one hundred forty-nine million, four hundred seventy-two thousand, sixty-seven".