Base | Representation |
---|---|
bin | 10010001110111100110… |
… | …111101111110001000101 |
3 | 11102210020000111010112012 |
4 | 102032330313233301011 |
5 | 131012123034311232 |
6 | 2355342220504005 |
7 | 156345420040133 |
oct | 22167467576105 |
9 | 4383200433465 |
10 | 1253004213317 |
11 | 44343a23806a |
12 | 182a106ab005 |
13 | 9120888593c |
14 | 44907c3a753 |
15 | 228d81a79b2 |
hex | 123bcdefc45 |
1253004213317 has 2 divisors, whose sum is σ = 1253004213318. Its totient is φ = 1253004213316.
The previous prime is 1253004213301. The next prime is 1253004213421. The reversal of 1253004213317 is 7133124003521.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1111993449121 + 141010764196 = 1054511^2 + 375514^2 .
It is a cyclic number.
It is not a de Polignac number, because 1253004213317 - 24 = 1253004213301 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1253006213317) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 626502106658 + 626502106659.
It is an arithmetic number, because the mean of its divisors is an integer number (626502106659).
Almost surely, 21253004213317 is an apocalyptic number.
It is an amenable number.
1253004213317 is a deficient number, since it is larger than the sum of its proper divisors (1).
1253004213317 is an equidigital number, since it uses as much as digits as its factorization.
1253004213317 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15120, while the sum is 32.
Adding to 1253004213317 its reverse (7133124003521), we get a palindrome (8386128216838).
The spelling of 1253004213317 in words is "one trillion, two hundred fifty-three billion, four million, two hundred thirteen thousand, three hundred seventeen".
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