Base | Representation |
---|---|
bin | 10111010101110000… |
… | …11111011110110011 |
3 | 1012100021120001101012 |
4 | 23222320133132303 |
5 | 201130314042042 |
6 | 5431222301135 |
7 | 622343305634 |
oct | 135270373663 |
9 | 35307501335 |
10 | 12530612147 |
11 | 5350227409 |
12 | 25185877ab |
13 | 1249077401 |
14 | 86c2a188b |
15 | 4d5133e82 |
hex | 2eae1f7b3 |
12530612147 has 2 divisors, whose sum is σ = 12530612148. Its totient is φ = 12530612146.
The previous prime is 12530612113. The next prime is 12530612179. The reversal of 12530612147 is 74121603521.
It is an a-pointer prime, because the next prime (12530612179) can be obtained adding 12530612147 to its sum of digits (32).
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12530612147 - 222 = 12526417843 is a prime.
It is not a weakly prime, because it can be changed into another prime (12530612197) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6265306073 + 6265306074.
It is an arithmetic number, because the mean of its divisors is an integer number (6265306074).
Almost surely, 212530612147 is an apocalyptic number.
12530612147 is a deficient number, since it is larger than the sum of its proper divisors (1).
12530612147 is an equidigital number, since it uses as much as digits as its factorization.
12530612147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10080, while the sum is 32.
The spelling of 12530612147 in words is "twelve billion, five hundred thirty million, six hundred twelve thousand, one hundred forty-seven".
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