1253094796800 has 2880 divisors, whose sum is σ = 6046273728000. Its totient is φ = 251983872000.

The previous prime is 1253094796777. The next prime is 1253094796843. The reversal of 1253094796800 is 86974903521.

1253094796800 is a `hidden beast` number, since 1 + 2 + 530 + 9 + 47 + 9 + 68 + 0 + 0 = 666.

It is a tau number, because it is divible by the number of its divisors (2880).

It is a Harshad number since it is a multiple of its sum of digits (54).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 287 ways as a sum of consecutive naturals, for example, 40422412785 + ... + 40422412815.

It is an arithmetic number, because the mean of its divisors is an integer number (2099400600).

It is a 1-persistent number, because it is pandigital, but 2⋅1253094796800 = 2506189593600 is not.

Almost surely, 2^{1253094796800} is an apocalyptic number.

1253094796800 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1253094796800, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (3023136864000).

1253094796800 is an abundant number, since it is smaller than the sum of its proper divisors (4793178931200).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1253094796800 is an equidigital number, since it uses as much as digits as its factorization.

1253094796800 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 131 (or 59 counting only the distinct ones).

The product of its (nonzero) digits is 3265920, while the sum is 54.

The spelling of 1253094796800 in words is "one trillion, two hundred fifty-three billion, ninety-four million, seven hundred ninety-six thousand, eight hundred".