Base | Representation |
---|---|
bin | 1011011001011010000110… |
… | …0011011100101000101100 |
3 | 1122100222000222221000101220 |
4 | 2312112201203130220230 |
5 | 3120302223241322130 |
6 | 42352415513503340 |
7 | 2432226040522626 |
oct | 266264143345054 |
9 | 48328028830356 |
10 | 12531130026540 |
11 | 3aa1471239a64 |
12 | 14a474a111b50 |
13 | 6cb8b00674b8 |
14 | 31471d363c16 |
15 | 16ae6b995410 |
hex | b65a18dca2c |
12531130026540 has 24 divisors (see below), whose sum is σ = 35087164074480. Its totient is φ = 3341634673728.
The previous prime is 12531130026523. The next prime is 12531130026659. The reversal of 12531130026540 is 4562003113521.
It is a super-2 number, since 2×125311300265402 (a number of 27 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 104426083495 + ... + 104426083614.
It is an arithmetic number, because the mean of its divisors is an integer number (1461965169770).
Almost surely, 212531130026540 is an apocalyptic number.
12531130026540 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
12531130026540 is an abundant number, since it is smaller than the sum of its proper divisors (22556034047940).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
12531130026540 is a wasteful number, since it uses less digits than its factorization.
12531130026540 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 208852167121 (or 208852167119 counting only the distinct ones).
The product of its (nonzero) digits is 21600, while the sum is 33.
The spelling of 12531130026540 in words is "twelve trillion, five hundred thirty-one billion, one hundred thirty million, twenty-six thousand, five hundred forty".
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