Base | Representation |
---|---|
bin | 111010010110100111… |
… | …1010110101001001001 |
3 | 102222110021121120120212 |
4 | 1310231033112221021 |
5 | 4023120120114314 |
6 | 133322405330505 |
7 | 12024242234423 |
oct | 1645517265111 |
9 | 388407546525 |
10 | 125313051209 |
11 | 49165a50135 |
12 | 20353106a35 |
13 | ba80b63358 |
14 | 60cac17813 |
15 | 33d6647e3e |
hex | 1d2d3d6a49 |
125313051209 has 2 divisors, whose sum is σ = 125313051210. Its totient is φ = 125313051208.
The previous prime is 125313051169. The next prime is 125313051211. The reversal of 125313051209 is 902150313521.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 105417102400 + 19895948809 = 324680^2 + 141053^2 .
It is a cyclic number.
It is not a de Polignac number, because 125313051209 - 236 = 56593574473 is a prime.
Together with 125313051211, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (125313050209) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62656525604 + 62656525605.
It is an arithmetic number, because the mean of its divisors is an integer number (62656525605).
Almost surely, 2125313051209 is an apocalyptic number.
It is an amenable number.
125313051209 is a deficient number, since it is larger than the sum of its proper divisors (1).
125313051209 is an equidigital number, since it uses as much as digits as its factorization.
125313051209 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8100, while the sum is 32.
The spelling of 125313051209 in words is "one hundred twenty-five billion, three hundred thirteen million, fifty-one thousand, two hundred nine".
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