12532540333 has 2 divisors, whose sum is σ = 12532540334. Its totient is φ = 12532540332.

The previous prime is 12532540331. The next prime is 12532540337. The reversal of 12532540333 is 33304523521.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11663352009 + 869188324 = 107997^2 + 29482^2 .

It is a cyclic number.

It is not a de Polignac number, because 12532540333 - 2¹ = 12532540331 is a prime.

Together with 12532540331, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 12532540295 and 12532540304.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12532540331) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6266270166 + 6266270167.

It is an arithmetic number, because the mean of its divisors is an integer number (6266270167).

Almost surely, 2^12532540333 is an apocalyptic number.

It is an amenable number.

12532540333 is a deficient number, since it is larger than the sum of its proper divisors (1).

12532540333 is an equidigital number, since it uses as much as digits as its factorization.

12532540333 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 32400, while the sum is 31.

The spelling of 12532540333 in words is "twelve billion, five hundred thirty-two million, five hundred forty thousand, three hundred thirty-three".