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12534553000127 is a prime number
BaseRepresentation
bin1011011001100110110110…
…0101000011100010111111
31122101021212112212002102102
42312121231211003202333
53120331231032001002
642354143312015315
72432406623362514
oct266315545034277
948337775762372
1012534553000127
113aa2968436754
1214a534453153b
136cc007275062
14314965bd130b
1516b0bc239a02
hexb666d9438bf

12534553000127 has 2 divisors, whose sum is σ = 12534553000128. Its totient is φ = 12534553000126.

The previous prime is 12534553000097. The next prime is 12534553000141. The reversal of 12534553000127 is 72100035543521.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 12534553000127 - 210 = 12534552999103 is a prime.

It is a super-2 number, since 2×125345530001272 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12534553000147) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6267276500063 + 6267276500064.

It is an arithmetic number, because the mean of its divisors is an integer number (6267276500064).

Almost surely, 212534553000127 is an apocalyptic number.

12534553000127 is a deficient number, since it is larger than the sum of its proper divisors (1).

12534553000127 is an equidigital number, since it uses as much as digits as its factorization.

12534553000127 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 126000, while the sum is 38.

Adding to 12534553000127 its reverse (72100035543521), we get a palindrome (84634588543648).

The spelling of 12534553000127 in words is "twelve trillion, five hundred thirty-four billion, five hundred fifty-three million, one hundred twenty-seven", and thus it is an aban number.