Base | Representation |
---|---|
bin | 1011011001101000100010… |
… | …0011001110011110011111 |
3 | 1122101100001002022202000102 |
4 | 2312122020203032132133 |
5 | 3120333142402133224 |
6 | 42354300234451315 |
7 | 2432424056535134 |
oct | 266321043163637 |
9 | 48340032282012 |
10 | 12535005505439 |
11 | 3aa307a90368a |
12 | 14a544bb93b3b |
13 | 6cc079c3b191 |
14 | 3149a9d4258b |
15 | 16b0e6d204ae |
hex | b66888ce79f |
12535005505439 has 2 divisors, whose sum is σ = 12535005505440. Its totient is φ = 12535005505438.
The previous prime is 12535005505417. The next prime is 12535005505453. The reversal of 12535005505439 is 93450550053521.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12535005505439 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 12535005505393 and 12535005505402.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12535005505409) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6267502752719 + 6267502752720.
It is an arithmetic number, because the mean of its divisors is an integer number (6267502752720).
Almost surely, 212535005505439 is an apocalyptic number.
12535005505439 is a deficient number, since it is larger than the sum of its proper divisors (1).
12535005505439 is an equidigital number, since it uses as much as digits as its factorization.
12535005505439 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2025000, while the sum is 47.
The spelling of 12535005505439 in words is "twelve trillion, five hundred thirty-five billion, five million, five hundred five thousand, four hundred thirty-nine".
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