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1253514144413 is a prime number
BaseRepresentation
bin10010001111011011010…
…000111110101010011101
311102211112120000022111002
4102033123100332222131
5131014144110110123
62355504554240045
7156364151265536
oct22173320765235
94384476008432
101253514144413
11443681067923
12182b33426025
139128a40710b
144495585968d
1522917d33528
hex123db43ea9d

1253514144413 has 2 divisors, whose sum is σ = 1253514144414. Its totient is φ = 1253514144412.

The previous prime is 1253514144391. The next prime is 1253514144473. The reversal of 1253514144413 is 3144414153521.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1253499681604 + 14462809 = 1119598^2 + 3803^2 .

It is a cyclic number.

It is not a de Polignac number, because 1253514144413 - 210 = 1253514143389 is a prime.

It is a super-2 number, since 2×12535141444132 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1253514144473) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 626757072206 + 626757072207.

It is an arithmetic number, because the mean of its divisors is an integer number (626757072207).

Almost surely, 21253514144413 is an apocalyptic number.

It is an amenable number.

1253514144413 is a deficient number, since it is larger than the sum of its proper divisors (1).

1253514144413 is an equidigital number, since it uses as much as digits as its factorization.

1253514144413 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 115200, while the sum is 38.

Adding to 1253514144413 its reverse (3144414153521), we get a palindrome (4397928297934).

The spelling of 1253514144413 in words is "one trillion, two hundred fifty-three billion, five hundred fourteen million, one hundred forty-four thousand, four hundred thirteen".