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12535413133 is a prime number
BaseRepresentation
bin10111010110010101…
…10011100110001101
31012100121120222002111
423223022303212031
5201133031210013
65431513224021
7622432152655
oct135312634615
935317528074
1012535413133
115352a06471
12251a102011
13124a068729
1486cb91365
154d578173d
hex2eb2b398d

12535413133 has 2 divisors, whose sum is σ = 12535413134. Its totient is φ = 12535413132.

The previous prime is 12535413119. The next prime is 12535413167. The reversal of 12535413133 is 33131453521.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12525414889 + 9998244 = 111917^2 + 3162^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12535413133 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 12535413095 and 12535413104.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12535413833) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6267706566 + 6267706567.

It is an arithmetic number, because the mean of its divisors is an integer number (6267706567).

Almost surely, 212535413133 is an apocalyptic number.

It is an amenable number.

12535413133 is a deficient number, since it is larger than the sum of its proper divisors (1).

12535413133 is an equidigital number, since it uses as much as digits as its factorization.

12535413133 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 16200, while the sum is 31.

Adding to 12535413133 its reverse (33131453521), we get a palindrome (45666866654).

The spelling of 12535413133 in words is "twelve billion, five hundred thirty-five million, four hundred thirteen thousand, one hundred thirty-three".