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125409901031 is a prime number
BaseRepresentation
bin111010011001100000…
…0110011100111100111
3102222201000212001120022
41310303000303213213
54023314413313111
6133340145225355
712026526366422
oct1646300634747
9388630761508
10125409901031
114920568a908
122037b63225b
13ba97c4303c
1460d9a289b9
1533dedc92db
hex1d330339e7

125409901031 has 2 divisors, whose sum is σ = 125409901032. Its totient is φ = 125409901030.

The previous prime is 125409901021. The next prime is 125409901081. The reversal of 125409901031 is 130109904521.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 125409901031 - 214 = 125409884647 is a prime.

It is a super-2 number, since 2×1254099010312 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 125409900982 and 125409901000.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (125409901021) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62704950515 + 62704950516.

It is an arithmetic number, because the mean of its divisors is an integer number (62704950516).

Almost surely, 2125409901031 is an apocalyptic number.

125409901031 is a deficient number, since it is larger than the sum of its proper divisors (1).

125409901031 is an equidigital number, since it uses as much as digits as its factorization.

125409901031 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 9720, while the sum is 35.

The spelling of 125409901031 in words is "one hundred twenty-five billion, four hundred nine million, nine hundred one thousand, thirty-one".