Base | Representation |
---|---|
bin | 111010011010011010… |
… | …0000101010111101111 |
3 | 102222210010201100121121 |
4 | 1310310310011113233 |
5 | 4023400132322203 |
6 | 133343145041411 |
7 | 12030344300311 |
oct | 1646464052757 |
9 | 388703640547 |
10 | 125440120303 |
11 | 49220750013 |
12 | 20389786267 |
13 | baa1293a74 |
14 | 60dda537b1 |
15 | 33e28980bd |
hex | 1d34d055ef |
125440120303 has 2 divisors, whose sum is σ = 125440120304. Its totient is φ = 125440120302.
The previous prime is 125440120291. The next prime is 125440120367. The reversal of 125440120303 is 303021044521.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 125440120303 - 217 = 125439989231 is a prime.
It is a super-4 number, since 4×1254401203034 (a number of 45 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (125440120103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62720060151 + 62720060152.
It is an arithmetic number, because the mean of its divisors is an integer number (62720060152).
Almost surely, 2125440120303 is an apocalyptic number.
125440120303 is a deficient number, since it is larger than the sum of its proper divisors (1).
125440120303 is an equidigital number, since it uses as much as digits as its factorization.
125440120303 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2880, while the sum is 25.
Adding to 125440120303 its reverse (303021044521), we get a palindrome (428461164824).
The spelling of 125440120303 in words is "one hundred twenty-five billion, four hundred forty million, one hundred twenty thousand, three hundred three".
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