12544031 has 2 divisors, whose sum is σ = 12544032. Its totient is φ = 12544030.

The previous prime is 12544027. The next prime is 12544033. The reversal of 12544031 is 13044521.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 12544031 - 2² = 12544027 is a prime.

It is a super-2 number, since 2×12544031² = 314705427457922, which contains 22 as substring.

Together with 12544033, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 12543994 and 12544012.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12544033) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6272015 + 6272016.

It is an arithmetic number, because the mean of its divisors is an integer number (6272016).

Almost surely, 2^12544031 is an apocalyptic number.

12544031 is a deficient number, since it is larger than the sum of its proper divisors (1).

12544031 is an equidigital number, since it uses as much as digits as its factorization.

12544031 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 480, while the sum is 20.

The square root of 12544031 is about 3541.7553557523. The cubic root of 12544031 is about 232.3516207458.

Adding to 12544031 its reverse (13044521), we get a palindrome (25588552).

The spelling of 12544031 in words is "twelve million, five hundred forty-four thousand, thirty-one".