Base | Representation |
---|---|
bin | 111010011010011101… |
… | …1011000100111011101 |
3 | 102222210021022120220111 |
4 | 1310310323120213131 |
5 | 4023401130043031 |
6 | 133343254050021 |
7 | 12030366461104 |
oct | 1646473304735 |
9 | 388707276814 |
10 | 125442034141 |
11 | 492218379a6 |
12 | 2038a349911 |
13 | baa17b3c08 |
14 | 60dddd103b |
15 | 33e2b251b1 |
hex | 1d34ed89dd |
125442034141 has 2 divisors, whose sum is σ = 125442034142. Its totient is φ = 125442034140.
The previous prime is 125442034051. The next prime is 125442034163. The reversal of 125442034141 is 141430244521.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 125408056900 + 33977241 = 354130^2 + 5829^2 .
It is an emirp because it is prime and its reverse (141430244521) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 125442034141 - 231 = 123294550493 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (125442034171) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62721017070 + 62721017071.
It is an arithmetic number, because the mean of its divisors is an integer number (62721017071).
Almost surely, 2125442034141 is an apocalyptic number.
It is an amenable number.
125442034141 is a deficient number, since it is larger than the sum of its proper divisors (1).
125442034141 is an equidigital number, since it uses as much as digits as its factorization.
125442034141 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15360, while the sum is 31.
Adding to 125442034141 its reverse (141430244521), we get a palindrome (266872278662).
The spelling of 125442034141 in words is "one hundred twenty-five billion, four hundred forty-two million, thirty-four thousand, one hundred forty-one".
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