Base | Representation |
---|---|
bin | 10010010000010001111… |
… | …011101110100001010000 |
3 | 11102220220110211200001121 |
4 | 102100101323232201100 |
5 | 131023033404221034 |
6 | 2400140000412024 |
7 | 156425656201342 |
oct | 22202173564120 |
9 | 4386813750047 |
10 | 1254431320144 |
11 | 4440018605a2 |
12 | 18314a617014 |
13 | 913a5435552 |
14 | 44a015a7292 |
15 | 2296d6041b4 |
hex | 12411eee850 |
1254431320144 has 10 divisors (see below), whose sum is σ = 2430460682810. Its totient is φ = 627215660064.
The previous prime is 1254431320127. The next prime is 1254431320189. The reversal of 1254431320144 is 4410231344521.
It can be written as a sum of positive squares in only one way, i.e., 820002691600 + 434428628544 = 905540^2 + 659112^2 .
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 39200978739 + ... + 39200978770.
It is an arithmetic number, because the mean of its divisors is an integer number (243046068281).
Almost surely, 21254431320144 is an apocalyptic number.
It is an amenable number.
1254431320144 is a deficient number, since it is larger than the sum of its proper divisors (1176029362666).
1254431320144 is an equidigital number, since it uses as much as digits as its factorization.
1254431320144 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 78401957517 (or 78401957511 counting only the distinct ones).
The product of its (nonzero) digits is 46080, while the sum is 34.
Adding to 1254431320144 its reverse (4410231344521), we get a palindrome (5664662664665).
The spelling of 1254431320144 in words is "one trillion, two hundred fifty-four billion, four hundred thirty-one million, three hundred twenty thousand, one hundred forty-four".
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