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125443264481 is a prime number
BaseRepresentation
bin111010011010100000…
…0000100111111100001
3102222210100122002121122
41310311000010333201
54023401433430411
6133343340302025
712030413104103
oct1646500047741
9388710562548
10125443264481
11492224a8307
122038a841915
13baa1b24c22
146100231573
1533e2cb99db
hex1d35004fe1

125443264481 has 2 divisors, whose sum is σ = 125443264482. Its totient is φ = 125443264480.

The previous prime is 125443264393. The next prime is 125443264483. The reversal of 125443264481 is 184462344521.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 84355974481 + 41087290000 = 290441^2 + 202700^2 .

It is a cyclic number.

It is not a de Polignac number, because 125443264481 - 218 = 125443002337 is a prime.

It is a super-3 number, since 3×1254432644813 (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

Together with 125443264483, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (125443264483) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62721632240 + 62721632241.

It is an arithmetic number, because the mean of its divisors is an integer number (62721632241).

Almost surely, 2125443264481 is an apocalyptic number.

It is an amenable number.

125443264481 is a deficient number, since it is larger than the sum of its proper divisors (1).

125443264481 is an equidigital number, since it uses as much as digits as its factorization.

125443264481 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 737280, while the sum is 44.

The spelling of 125443264481 in words is "one hundred twenty-five billion, four hundred forty-three million, two hundred sixty-four thousand, four hundred eighty-one".