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12545101134053 is a prime number
BaseRepresentation
bin1011011010001110001001…
…0010111111100011100101
31122102022002200000210221022
42312203202102333203211
53121014331342242203
642403050115100525
72433232205134535
oct266434222774345
948368080023838
1012545101134053
113aa73905a3904
1214a73a8ba1745
136cccc869b517
14315286a794c5
1516b4d82bca38
hexb68e24bf8e5

12545101134053 has 2 divisors, whose sum is σ = 12545101134054. Its totient is φ = 12545101134052.

The previous prime is 12545101134047. The next prime is 12545101134143. The reversal of 12545101134053 is 35043110154521.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12220072301284 + 325028832769 = 3495722^2 + 570113^2 .

It is a cyclic number.

It is not a de Polignac number, because 12545101134053 - 24 = 12545101134037 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12545101134353) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6272550567026 + 6272550567027.

It is an arithmetic number, because the mean of its divisors is an integer number (6272550567027).

Almost surely, 212545101134053 is an apocalyptic number.

It is an amenable number.

12545101134053 is a deficient number, since it is larger than the sum of its proper divisors (1).

12545101134053 is an equidigital number, since it uses as much as digits as its factorization.

12545101134053 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 36000, while the sum is 35.

Adding to 12545101134053 its reverse (35043110154521), we get a palindrome (47588211288574).

The spelling of 12545101134053 in words is "twelve trillion, five hundred forty-five billion, one hundred one million, one hundred thirty-four thousand, fifty-three".