Base | Representation |
---|---|
bin | 1011011010001110111001… |
… | …0101011100001001100010 |
3 | 1122102022121202001211221111 |
4 | 2312203232111130021202 |
5 | 3121020240043231200 |
6 | 42403122132013534 |
7 | 2433240206626525 |
oct | 266435625341142 |
9 | 48368552054844 |
10 | 12545303102050 |
11 | 3aa7484600404 |
12 | 14a74447612aa |
13 | 70002b494504 |
14 | 3152a5810bbc |
15 | 16b4eadb50ba |
hex | b68ee55c262 |
12545303102050 has 24 divisors (see below), whose sum is σ = 23407873464276. Its totient is φ = 5002291199040.
The previous prime is 12545303102041. The next prime is 12545303102081. The reversal of 12545303102050 is 5020130354521.
12545303102050 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It can be written as a sum of positive squares in 6 ways, for example, as 1764186963529 + 10781116138521 = 1328227^2 + 3283461^2 .
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 395735037 + ... + 395766736.
Almost surely, 212545303102050 is an apocalyptic number.
12545303102050 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
12545303102050 is a deficient number, since it is larger than the sum of its proper divisors (10862570362226).
12545303102050 is a wasteful number, since it uses less digits than its factorization.
12545303102050 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 791502102 (or 791502097 counting only the distinct ones).
The product of its (nonzero) digits is 18000, while the sum is 31.
Adding to 12545303102050 its reverse (5020130354521), we get a palindrome (17565433456571).
The spelling of 12545303102050 in words is "twelve trillion, five hundred forty-five billion, three hundred three million, one hundred two thousand, fifty".
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