Search a number
-
+
12552047 is a prime number
BaseRepresentation
bin101111111000…
…011101101111
3212121201011122
4233320131233
511203131142
61125011155
7211455614
oct57703557
925551148
1012552047
1170a35a2
124253abb
1327a6361
14194a50b
15117e1d2
hexbf876f

12552047 has 2 divisors, whose sum is σ = 12552048. Its totient is φ = 12552046.

The previous prime is 12552037. The next prime is 12552049. The reversal of 12552047 is 74025521.

It is a strong prime.

It is an emirp because it is prime and its reverse (74025521) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12552047 is a prime.

Together with 12552049, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12552049) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6276023 + 6276024.

It is an arithmetic number, because the mean of its divisors is an integer number (6276024).

Almost surely, 212552047 is an apocalyptic number.

12552047 is a deficient number, since it is larger than the sum of its proper divisors (1).

12552047 is an equidigital number, since it uses as much as digits as its factorization.

12552047 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2800, while the sum is 26.

The square root of 12552047 is about 3542.8868172720. The cubic root of 12552047 is about 232.4011033509.

Adding to 12552047 its reverse (74025521), we get a palindrome (86577568).

The spelling of 12552047 in words is "twelve million, five hundred fifty-two thousand, forty-seven".