Base | Representation |
---|---|
bin | 111010011100111100… |
… | …0011101001000110011 |
3 | 110000000001201102121002 |
4 | 1310321320131020303 |
5 | 4024033414333212 |
6 | 133355423352215 |
7 | 12032426122112 |
oct | 1647170351063 |
9 | 400001642532 |
10 | 125525152307 |
11 | 492647488a5 |
12 | 203b215266b |
13 | bab5a96669 |
14 | 610b069c79 |
15 | 33ea092ac2 |
hex | 1d39e1d233 |
125525152307 has 2 divisors, whose sum is σ = 125525152308. Its totient is φ = 125525152306.
The previous prime is 125525152303. The next prime is 125525152309. The reversal of 125525152307 is 703251525521.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 125525152307 - 22 = 125525152303 is a prime.
Together with 125525152309, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (125525152303) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62762576153 + 62762576154.
It is an arithmetic number, because the mean of its divisors is an integer number (62762576154).
Almost surely, 2125525152307 is an apocalyptic number.
125525152307 is a deficient number, since it is larger than the sum of its proper divisors (1).
125525152307 is an equidigital number, since it uses as much as digits as its factorization.
125525152307 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 105000, while the sum is 38.
Adding to 125525152307 its reverse (703251525521), we get a palindrome (828776677828).
The spelling of 125525152307 in words is "one hundred twenty-five billion, five hundred twenty-five million, one hundred fifty-two thousand, three hundred seven".
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