Base | Representation |
---|---|
bin | 10010010001000111001… |
… | …101000110000010010111 |
3 | 11110000012202120122000112 |
4 | 102101013031012002113 |
5 | 131031401204042432 |
6 | 2400404404433235 |
7 | 156460060666502 |
oct | 22210715060227 |
9 | 4400182518015 |
10 | 1255325065367 |
11 | 44442030060a |
12 | 1833599a881b |
13 | 914b864bc89 |
14 | 44a88176139 |
15 | 229c1ce77b2 |
hex | 12447346097 |
1255325065367 has 2 divisors, whose sum is σ = 1255325065368. Its totient is φ = 1255325065366.
The previous prime is 1255325065327. The next prime is 1255325065369. The reversal of 1255325065367 is 7635605235521.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1255325065367 - 214 = 1255325048983 is a prime.
It is a super-3 number, since 3×12553250653673 (a number of 37 digits) contains 333 as substring.
Together with 1255325065369, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1255325065369) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 627662532683 + 627662532684.
It is an arithmetic number, because the mean of its divisors is an integer number (627662532684).
Almost surely, 21255325065367 is an apocalyptic number.
1255325065367 is a deficient number, since it is larger than the sum of its proper divisors (1).
1255325065367 is an equidigital number, since it uses as much as digits as its factorization.
1255325065367 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5670000, while the sum is 50.
The spelling of 1255325065367 in words is "one trillion, two hundred fifty-five billion, three hundred twenty-five million, sixty-five thousand, three hundred sixty-seven".
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