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125533041133 is a prime number
BaseRepresentation
bin111010011101001011…
…0100011000111101101
3110000000121120020000211
41310322112203013231
54024042424304013
6133400304422421
712032553146443
oct1647226430755
9400017506024
10125533041133
1149269146895
12203b4917a11
13bab75c92c6
14610c120b93
1533eab0023d
hex1d3a5a31ed

125533041133 has 2 divisors, whose sum is σ = 125533041134. Its totient is φ = 125533041132.

The previous prime is 125533041121. The next prime is 125533041167. The reversal of 125533041133 is 331140335521.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 120556867369 + 4976173764 = 347213^2 + 70542^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-125533041133 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 125533041095 and 125533041104.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (125533041103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62766520566 + 62766520567.

It is an arithmetic number, because the mean of its divisors is an integer number (62766520567).

Almost surely, 2125533041133 is an apocalyptic number.

It is an amenable number.

125533041133 is a deficient number, since it is larger than the sum of its proper divisors (1).

125533041133 is an equidigital number, since it uses as much as digits as its factorization.

125533041133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 16200, while the sum is 31.

Adding to 125533041133 its reverse (331140335521), we get a palindrome (456673376654).

The spelling of 125533041133 in words is "one hundred twenty-five billion, five hundred thirty-three million, forty-one thousand, one hundred thirty-three".