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12554332013 is a prime number
BaseRepresentation
bin10111011000100101…
…11110011101101101
31012101221012010220202
423230102332131231
5201202402111023
65433430523245
7623052030026
oct135422763555
935357163822
1012554332013
115362658503
122524506525
131250c60a32
148714b7c4d
154d726c128
hex2ec4be76d

12554332013 has 2 divisors, whose sum is σ = 12554332014. Its totient is φ = 12554332012.

The previous prime is 12554332003. The next prime is 12554332039. The reversal of 12554332013 is 31023345521.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9552716644 + 3001615369 = 97738^2 + 54787^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12554332013 is a prime.

It is a super-2 number, since 2×125543320132 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12554332003) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6277166006 + 6277166007.

It is an arithmetic number, because the mean of its divisors is an integer number (6277166007).

Almost surely, 212554332013 is an apocalyptic number.

It is an amenable number.

12554332013 is a deficient number, since it is larger than the sum of its proper divisors (1).

12554332013 is an equidigital number, since it uses as much as digits as its factorization.

12554332013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 10800, while the sum is 29.

Adding to 12554332013 its reverse (31023345521), we get a palindrome (43577677534).

The spelling of 12554332013 in words is "twelve billion, five hundred fifty-four million, three hundred thirty-two thousand, thirteen".