Base | Representation |
---|---|
bin | 10111011001110111… |
… | …00101011111110011 |
3 | 1012102200012222222122 |
4 | 23230323211133303 |
5 | 201213113241101 |
6 | 5434451024455 |
7 | 623241355622 |
oct | 135473453763 |
9 | 35380188878 |
10 | 12564977651 |
11 | 5368669756 |
12 | 2527b9b12b |
13 | 125321a425 |
14 | 872a896b9 |
15 | 4d817151b |
hex | 2ecee57f3 |
12564977651 has 2 divisors, whose sum is σ = 12564977652. Its totient is φ = 12564977650.
The previous prime is 12564977599. The next prime is 12564977653. The reversal of 12564977651 is 15677946521.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12564977651 - 26 = 12564977587 is a prime.
Together with 12564977653, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 12564977593 and 12564977602.
It is not a weakly prime, because it can be changed into another prime (12564977653) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6282488825 + 6282488826.
It is an arithmetic number, because the mean of its divisors is an integer number (6282488826).
Almost surely, 212564977651 is an apocalyptic number.
12564977651 is a deficient number, since it is larger than the sum of its proper divisors (1).
12564977651 is an equidigital number, since it uses as much as digits as its factorization.
12564977651 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 3175200, while the sum is 53.
The spelling of 12564977651 in words is "twelve billion, five hundred sixty-four million, nine hundred seventy-seven thousand, six hundred fifty-one".
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