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12568536951661 is a prime number
BaseRepresentation
bin1011011011100101011100…
…1011100010101101101101
31122111112120221122200220001
42312321113023202231231
53121410330424423121
642421523422024301
72435022030244435
oct266712713425555
948445527580801
1012568536951661
1140063174a2509
1214aba49718091
13702291b2cc12
1431646b3b32c5
1516be0a9b8991
hexb6e572e2b6d

12568536951661 has 2 divisors, whose sum is σ = 12568536951662. Its totient is φ = 12568536951660.

The previous prime is 12568536951643. The next prime is 12568536951823. The reversal of 12568536951661 is 16615963586521.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 7259171661225 + 5309365290436 = 2694285^2 + 2304206^2 .

It is a cyclic number.

It is not a de Polignac number, because 12568536951661 - 219 = 12568536427373 is a prime.

It is a super-2 number, since 2×125685369516612 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 12568536951593 and 12568536951602.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12568536952661) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6284268475830 + 6284268475831.

It is an arithmetic number, because the mean of its divisors is an integer number (6284268475831).

Almost surely, 212568536951661 is an apocalyptic number.

It is an amenable number.

12568536951661 is a deficient number, since it is larger than the sum of its proper divisors (1).

12568536951661 is an equidigital number, since it uses as much as digits as its factorization.

12568536951661 is an evil number, because the sum of its binary digits is even.

The product of its digits is 69984000, while the sum is 64.

The spelling of 12568536951661 in words is "twelve trillion, five hundred sixty-eight billion, five hundred thirty-six million, nine hundred fifty-one thousand, six hundred sixty-one".