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125741836433 is a prime number
BaseRepresentation
bin111010100011011001…
…1000010100010010001
3110000120011110010100002
41311012303002202101
54030004402231213
6133433123535345
712040666655213
oct1650663024221
9400504403302
10125741836433
1149365a96894
122045282a555
13bb1b942a15
14612bb525b3
15340e0e5658
hex1d46cc2891

125741836433 has 2 divisors, whose sum is σ = 125741836434. Its totient is φ = 125741836432.

The previous prime is 125741836411. The next prime is 125741836459. The reversal of 125741836433 is 334638147521.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 121683764224 + 4058072209 = 348832^2 + 63703^2 .

It is a cyclic number.

It is not a de Polignac number, because 125741836433 - 28 = 125741836177 is a prime.

It is a super-2 number, since 2×1257418364332 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (125741836933) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62870918216 + 62870918217.

It is an arithmetic number, because the mean of its divisors is an integer number (62870918217).

Almost surely, 2125741836433 is an apocalyptic number.

It is an amenable number.

125741836433 is a deficient number, since it is larger than the sum of its proper divisors (1).

125741836433 is an equidigital number, since it uses as much as digits as its factorization.

125741836433 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1451520, while the sum is 47.

The spelling of 125741836433 in words is "one hundred twenty-five billion, seven hundred forty-one million, eight hundred thirty-six thousand, four hundred thirty-three".