Base | Representation |
---|---|
bin | 111010101011011111… |
… | …0100011110100010111 |
3 | 110001021002020111002112 |
4 | 1311112332203310113 |
5 | 4031033400314144 |
6 | 133520102101235 |
7 | 12050504210243 |
oct | 1652676436427 |
9 | 401232214075 |
10 | 126013291799 |
11 | 4949524426a |
12 | 2050971a81b |
13 | bb62c580b5 |
14 | 6155c15423 |
15 | 3427d6699e |
hex | 1d56fa3d17 |
126013291799 has 2 divisors, whose sum is σ = 126013291800. Its totient is φ = 126013291798.
The previous prime is 126013291783. The next prime is 126013291801. The reversal of 126013291799 is 997192310621.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 126013291799 - 24 = 126013291783 is a prime.
It is a super-3 number, since 3×1260132917993 (a number of 34 digits) contains 333 as substring.
Together with 126013291801, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (126013291759) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 63006645899 + 63006645900.
It is an arithmetic number, because the mean of its divisors is an integer number (63006645900).
Almost surely, 2126013291799 is an apocalyptic number.
126013291799 is a deficient number, since it is larger than the sum of its proper divisors (1).
126013291799 is an equidigital number, since it uses as much as digits as its factorization.
126013291799 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 367416, while the sum is 50.
The spelling of 126013291799 in words is "one hundred twenty-six billion, thirteen million, two hundred ninety-one thousand, seven hundred ninety-nine".
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