Base | Representation |
---|---|
bin | 1011011101100000111000… |
… | …0011101011101111101111 |
3 | 1122121201010001010111222101 |
4 | 2313120032003223233233 |
5 | 3122431204443034403 |
6 | 42445043251555531 |
7 | 2440304061510364 |
oct | 267301603535757 |
9 | 48551101114871 |
10 | 12601669893103 |
11 | 401937a147845 |
12 | 14b63558bbba7 |
13 | 7054422b4b05 |
14 | 317cd194c46b |
15 | 16cbe969671d |
hex | b760e0ebbef |
12601669893103 has 2 divisors, whose sum is σ = 12601669893104. Its totient is φ = 12601669893102.
The previous prime is 12601669893101. The next prime is 12601669893187. The reversal of 12601669893103 is 30139896610621.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12601669893103 - 21 = 12601669893101 is a prime.
Together with 12601669893101, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12601669893101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6300834946551 + 6300834946552.
It is an arithmetic number, because the mean of its divisors is an integer number (6300834946552).
Almost surely, 212601669893103 is an apocalyptic number.
12601669893103 is a deficient number, since it is larger than the sum of its proper divisors (1).
12601669893103 is an equidigital number, since it uses as much as digits as its factorization.
12601669893103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2519424, while the sum is 55.
The spelling of 12601669893103 in words is "twelve trillion, six hundred one billion, six hundred sixty-nine million, eight hundred ninety-three thousand, one hundred three".
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