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126100115065541 is a prime number
BaseRepresentation
bin11100101010111111111000…
…100100001000101011000101
3121112111001102211110212100002
4130222333320210020223011
5113012011013424044131
61124105332041131045
735363301255544031
oct3452777044105305
9545431384425302
10126100115065541
11371a7838593151
1212187069489a85
135549261086106
14231d3c72b31c1
15e8a2479a66cb
hex72aff8908ac5

126100115065541 has 2 divisors, whose sum is σ = 126100115065542. Its totient is φ = 126100115065540.

The previous prime is 126100115065469. The next prime is 126100115065553. The reversal of 126100115065541 is 145560511001621.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 65363748496225 + 60736366569316 = 8084785^2 + 7793354^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-126100115065541 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 126100115065495 and 126100115065504.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (126100115065591) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 63050057532770 + 63050057532771.

It is an arithmetic number, because the mean of its divisors is an integer number (63050057532771).

Almost surely, 2126100115065541 is an apocalyptic number.

It is an amenable number.

126100115065541 is a deficient number, since it is larger than the sum of its proper divisors (1).

126100115065541 is an equidigital number, since it uses as much as digits as its factorization.

126100115065541 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 36000, while the sum is 38.

The spelling of 126100115065541 in words is "one hundred twenty-six trillion, one hundred billion, one hundred fifteen million, sixty-five thousand, five hundred forty-one".