Search a number
-
+
12610555453 is a prime number
BaseRepresentation
bin10111011111010010…
…11100111000111101
31012112211222120222101
423233221130320331
5201311300233303
65443155545101
7624333644536
oct135751347075
935484876871
1012610555453
115391369a61
12253b2bb191
13125c7b7a42
14878b5168d
154dc175d1d
hex2efa5ce3d

12610555453 has 2 divisors, whose sum is σ = 12610555454. Its totient is φ = 12610555452.

The previous prime is 12610555427. The next prime is 12610555457. The reversal of 12610555453 is 35455501621.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8641933444 + 3968622009 = 92962^2 + 62997^2 .

It is an emirp because it is prime and its reverse (35455501621) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12610555453 is a prime.

It is a super-2 number, since 2×126105554532 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12610555457) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6305277726 + 6305277727.

It is an arithmetic number, because the mean of its divisors is an integer number (6305277727).

Almost surely, 212610555453 is an apocalyptic number.

It is an amenable number.

12610555453 is a deficient number, since it is larger than the sum of its proper divisors (1).

12610555453 is an equidigital number, since it uses as much as digits as its factorization.

12610555453 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 90000, while the sum is 37.

The spelling of 12610555453 in words is "twelve billion, six hundred ten million, five hundred fifty-five thousand, four hundred fifty-three".