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12613014133 is a prime number
BaseRepresentation
bin10111011111100101…
…10101001001110101
31012120000121111122121
423233302311021311
5201312412423013
65443324355541
7624363564646
oct135762651165
935500544577
1012613014133
115392799225
1225400a5bb1
131260168b95
148791d16cd
154dc4ae58d
hex2efcb5275

12613014133 has 2 divisors, whose sum is σ = 12613014134. Its totient is φ = 12613014132.

The previous prime is 12613014097. The next prime is 12613014149. The reversal of 12613014133 is 33141031621.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6416490609 + 6196523524 = 80103^2 + 78718^2 .

It is a cyclic number.

It is not a de Polignac number, because 12613014133 - 225 = 12579459701 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 12613014098 and 12613014107.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12613014433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6306507066 + 6306507067.

It is an arithmetic number, because the mean of its divisors is an integer number (6306507067).

Almost surely, 212613014133 is an apocalyptic number.

It is an amenable number.

12613014133 is a deficient number, since it is larger than the sum of its proper divisors (1).

12613014133 is an equidigital number, since it uses as much as digits as its factorization.

12613014133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 12613014133 its reverse (33141031621), we get a palindrome (45754045754).

The spelling of 12613014133 in words is "twelve billion, six hundred thirteen million, fourteen thousand, one hundred thirty-three".