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12625015471 is a prime number
BaseRepresentation
bin10111100001000001…
…00111001010101111
31012120212012020101121
423300200213022233
5201324000443341
65444433521411
7624600601165
oct136040471257
935525166347
1012625015471
115399545a92
122544113267
1312627ab673
1487aa37235
154dd5804d1
hex2f08272af

12625015471 has 2 divisors, whose sum is σ = 12625015472. Its totient is φ = 12625015470.

The previous prime is 12625015463. The next prime is 12625015553. The reversal of 12625015471 is 17451052621.

12625015471 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is an emirp because it is prime and its reverse (17451052621) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12625015471 - 23 = 12625015463 is a prime.

It is a super-3 number, since 3×126250154713 (a number of 31 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12625010471) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6312507735 + 6312507736.

It is an arithmetic number, because the mean of its divisors is an integer number (6312507736).

Almost surely, 212625015471 is an apocalyptic number.

12625015471 is a deficient number, since it is larger than the sum of its proper divisors (1).

12625015471 is an equidigital number, since it uses as much as digits as its factorization.

12625015471 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 16800, while the sum is 34.

The spelling of 12625015471 in words is "twelve billion, six hundred twenty-five million, fifteen thousand, four hundred seventy-one".