Base | Representation |
---|---|
bin | 10111100001000100… |
… | …00110000001110001 |
3 | 1012120212220222101012 |
4 | 23300202012001301 |
5 | 201324100412032 |
6 | 5444450120305 |
7 | 624604110032 |
oct | 136042060161 |
9 | 35525828335 |
10 | 12625404017 |
11 | 53997909a6 |
12 | 2544280095 |
13 | 12628b6485 |
14 | 87aad8a89 |
15 | 4dd60a6b2 |
hex | 2f0886071 |
12625404017 has 2 divisors, whose sum is σ = 12625404018. Its totient is φ = 12625404016.
The previous prime is 12625403977. The next prime is 12625404019. The reversal of 12625404017 is 71040452621.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11000024161 + 1625379856 = 104881^2 + 40316^2 .
It is a cyclic number.
It is not a de Polignac number, because 12625404017 - 28 = 12625403761 is a prime.
Together with 12625404019, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (12625404019) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6312702008 + 6312702009.
It is an arithmetic number, because the mean of its divisors is an integer number (6312702009).
Almost surely, 212625404017 is an apocalyptic number.
It is an amenable number.
12625404017 is a deficient number, since it is larger than the sum of its proper divisors (1).
12625404017 is an equidigital number, since it uses as much as digits as its factorization.
12625404017 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 13440, while the sum is 32.
Adding to 12625404017 its reverse (71040452621), we get a palindrome (83665856638).
The spelling of 12625404017 in words is "twelve billion, six hundred twenty-five million, four hundred four thousand, seventeen".
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