Base | Representation |
---|---|
bin | 10010011000101101010… |
… | …010110110001001100101 |
3 | 11110210021010002110222121 |
4 | 102120231102312021211 |
5 | 131200101424101013 |
6 | 2404233531425541 |
7 | 160166135231242 |
oct | 22305522661145 |
9 | 4423233073877 |
10 | 1263480300133 |
11 | 447925766157 |
12 | 184a54bb52b1 |
13 | 921b80a488c |
14 | 4521d2cc5c9 |
15 | 22cecc5858d |
hex | 1262d4b6265 |
1263480300133 has 2 divisors, whose sum is σ = 1263480300134. Its totient is φ = 1263480300132.
The previous prime is 1263480300113. The next prime is 1263480300151. The reversal of 1263480300133 is 3310030843621.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1263337784289 + 142515844 = 1123983^2 + 11938^2 .
It is a cyclic number.
It is not a de Polignac number, because 1263480300133 - 229 = 1262943429221 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1263480300113) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 631740150066 + 631740150067.
It is an arithmetic number, because the mean of its divisors is an integer number (631740150067).
Almost surely, 21263480300133 is an apocalyptic number.
It is an amenable number.
1263480300133 is a deficient number, since it is larger than the sum of its proper divisors (1).
1263480300133 is an equidigital number, since it uses as much as digits as its factorization.
1263480300133 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 31104, while the sum is 34.
The spelling of 1263480300133 in words is "one trillion, two hundred sixty-three billion, four hundred eighty million, three hundred thousand, one hundred thirty-three".
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