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12636951412807 is a prime number
BaseRepresentation
bin1011011111100100010100…
…0000000000000001000111
31122202002011212112102100101
42313321011000000001013
53124020434030202212
642513200233224531
72442663302464021
oct267710500000107
948662155472311
1012636951412807
11403233469a797
121501161562147
13708875935aa7
143198bb5bb011
1516dab1cd5157
hexb7e45000047

12636951412807 has 2 divisors, whose sum is σ = 12636951412808. Its totient is φ = 12636951412806.

The previous prime is 12636951412777. The next prime is 12636951412837. The reversal of 12636951412807 is 70821415963621.

It is a balanced prime because it is at equal distance from previous prime (12636951412777) and next prime (12636951412837).

It is a cyclic number.

It is not a de Polignac number, because 12636951412807 - 231 = 12634803929159 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12636951412837) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6318475706403 + 6318475706404.

It is an arithmetic number, because the mean of its divisors is an integer number (6318475706404).

It is a 2-persistent number, because it is pandigital, and so is 2⋅12636951412807 = 25273902825614, but 3⋅12636951412807 = 37910854238421 is not.

Almost surely, 212636951412807 is an apocalyptic number.

12636951412807 is a deficient number, since it is larger than the sum of its proper divisors (1).

12636951412807 is an equidigital number, since it uses as much as digits as its factorization.

12636951412807 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4354560, while the sum is 55.

The spelling of 12636951412807 in words is "twelve trillion, six hundred thirty-six billion, nine hundred fifty-one million, four hundred twelve thousand, eight hundred seven".