Base | Representation |
---|---|
bin | 111010110110101011… |
… | …0110100101111110111 |
3 | 110002020020201210202212 |
4 | 1311231112310233313 |
5 | 4032321010020401 |
6 | 134021233324035 |
7 | 12063013442432 |
oct | 1655526645767 |
9 | 402206653685 |
10 | 126388751351 |
11 | 49668178615 |
12 | 205b340661b |
13 | bbc2986705 |
14 | 618da2c819 |
15 | 344accddbb |
hex | 1d6d5b4bf7 |
126388751351 has 2 divisors, whose sum is σ = 126388751352. Its totient is φ = 126388751350.
The previous prime is 126388751347. The next prime is 126388751353. The reversal of 126388751351 is 153157883621.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 126388751351 - 22 = 126388751347 is a prime.
Together with 126388751353, it forms a pair of twin primes.
It is a Chen prime.
It is a self number, because there is not a number n which added to its sum of digits gives 126388751351.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (126388751353) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 63194375675 + 63194375676.
It is an arithmetic number, because the mean of its divisors is an integer number (63194375676).
Almost surely, 2126388751351 is an apocalyptic number.
126388751351 is a deficient number, since it is larger than the sum of its proper divisors (1).
126388751351 is an equidigital number, since it uses as much as digits as its factorization.
126388751351 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1209600, while the sum is 50.
The spelling of 126388751351 in words is "one hundred twenty-six billion, three hundred eighty-eight million, seven hundred fifty-one thousand, three hundred fifty-one".
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