Base | Representation |
---|---|
bin | 111010111010000010… |
… | …0010001110110001101 |
3 | 110002112002120102002012 |
4 | 1311310010101312031 |
5 | 4033033320032232 |
6 | 134040334311005 |
7 | 12065551365125 |
oct | 1656404216615 |
9 | 402462512065 |
10 | 126501330317 |
11 | 4971578088a |
12 | 20625058465 |
13 | bc100b289b |
14 | 61a0975c85 |
15 | 3455b1a9b2 |
hex | 1d74111d8d |
126501330317 has 2 divisors, whose sum is σ = 126501330318. Its totient is φ = 126501330316.
The previous prime is 126501330313. The next prime is 126501330379. The reversal of 126501330317 is 713033105621.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 119397200521 + 7104129796 = 345539^2 + 84286^2 .
It is a cyclic number.
It is not a de Polignac number, because 126501330317 - 22 = 126501330313 is a prime.
It is a super-3 number, since 3×1265013303173 (a number of 34 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (126501330313) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 63250665158 + 63250665159.
It is an arithmetic number, because the mean of its divisors is an integer number (63250665159).
Almost surely, 2126501330317 is an apocalyptic number.
It is an amenable number.
126501330317 is a deficient number, since it is larger than the sum of its proper divisors (1).
126501330317 is an equidigital number, since it uses as much as digits as its factorization.
126501330317 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 11340, while the sum is 32.
Adding to 126501330317 its reverse (713033105621), we get a palindrome (839534435938).
The spelling of 126501330317 in words is "one hundred twenty-six billion, five hundred one million, three hundred thirty thousand, three hundred seventeen".
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