Base | Representation |
---|---|
bin | 1011100000100000111100… |
… | …1000100110010101000111 |
3 | 1122210122012011222200200002 |
4 | 2320020033020212111013 |
5 | 3124302302224111112 |
6 | 42524451255511515 |
7 | 2444110526504621 |
oct | 270101710462507 |
9 | 48718164880602 |
10 | 12653227566407 |
11 | 40392271018aa |
12 | 150434438859b |
13 | 70a26a98a9cc |
14 | 31a5c30b5c11 |
15 | 16e215b791c2 |
hex | b820f226547 |
12653227566407 has 2 divisors, whose sum is σ = 12653227566408. Its totient is φ = 12653227566406.
The previous prime is 12653227566389. The next prime is 12653227566409. The reversal of 12653227566407 is 70466572235621.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12653227566407 - 220 = 12653226517831 is a prime.
Together with 12653227566409, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12653227566409) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6326613783203 + 6326613783204.
It is an arithmetic number, because the mean of its divisors is an integer number (6326613783204).
Almost surely, 212653227566407 is an apocalyptic number.
12653227566407 is a deficient number, since it is larger than the sum of its proper divisors (1).
12653227566407 is an equidigital number, since it uses as much as digits as its factorization.
12653227566407 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 25401600, while the sum is 56.
The spelling of 12653227566407 in words is "twelve trillion, six hundred fifty-three billion, two hundred twenty-seven million, five hundred sixty-six thousand, four hundred seven".
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