Base | Representation |
---|---|
bin | 1011100001001101101111… |
… | …1101011011100110110111 |
3 | 1122211210020022122212201120 |
4 | 2320103123331123212313 |
5 | 3130001414444342100 |
6 | 42534200505555023 |
7 | 2445014540621025 |
oct | 270233375334667 |
9 | 48753208585646 |
10 | 12665253902775 |
11 | 4043338711371 |
12 | 150673baa5a73 |
13 | 70b436413a86 |
14 | 31b0043cb715 |
15 | 16e6bb89d0a0 |
hex | b84dbf5b9b7 |
12665253902775 has 24 divisors (see below), whose sum is σ = 21450615395664. Its totient is φ = 6590050809600.
The previous prime is 12665253902737. The next prime is 12665253902813. The reversal of 12665253902775 is 57720935256621.
It is an interprime number because it is at equal distance from previous prime (12665253902737) and next prime (12665253902813).
It is not a de Polignac number, because 12665253902775 - 212 = 12665253898679 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 2059387804 + ... + 2059393953.
It is an arithmetic number, because the mean of its divisors is an integer number (893775641486).
Almost surely, 212665253902775 is an apocalyptic number.
12665253902775 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
12665253902775 is a deficient number, since it is larger than the sum of its proper divisors (8785361492889).
12665253902775 is a wasteful number, since it uses less digits than its factorization.
12665253902775 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4118781811 (or 4118781806 counting only the distinct ones).
The product of its (nonzero) digits is 47628000, while the sum is 60.
The spelling of 12665253902775 in words is "twelve trillion, six hundred sixty-five billion, two hundred fifty-three million, nine hundred two thousand, seven hundred seventy-five".
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