Base | Representation |
---|---|
bin | 1011100001100011100110… |
… | …0100110010010010110101 |
3 | 1122212100101002202110010222 |
4 | 2320120321210302102311 |
5 | 3130100423040431301 |
6 | 42541010521224125 |
7 | 2445313103244302 |
oct | 270307144622265 |
9 | 48770332673128 |
10 | 12671119467701 |
11 | 4045878671092 |
12 | 15078b8332045 |
13 | 70bb5c6a0456 |
14 | 31b3dd4040a9 |
15 | 16e9117cd31b |
hex | b86399324b5 |
12671119467701 has 2 divisors, whose sum is σ = 12671119467702. Its totient is φ = 12671119467700.
The previous prime is 12671119467691. The next prime is 12671119467737. The reversal of 12671119467701 is 10776491117621.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 8932596675025 + 3738522792676 = 2988745^2 + 1933526^2 .
It is a cyclic number.
It is not a de Polignac number, because 12671119467701 - 242 = 8273072956597 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12671119467901) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6335559733850 + 6335559733851.
It is an arithmetic number, because the mean of its divisors is an integer number (6335559733851).
Almost surely, 212671119467701 is an apocalyptic number.
It is an amenable number.
12671119467701 is a deficient number, since it is larger than the sum of its proper divisors (1).
12671119467701 is an equidigital number, since it uses as much as digits as its factorization.
12671119467701 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 889056, while the sum is 53.
The spelling of 12671119467701 in words is "twelve trillion, six hundred seventy-one billion, one hundred nineteen million, four hundred sixty-seven thousand, seven hundred one".
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