Base | Representation |
---|---|
bin | 1011100010001000010011… |
… | …0010001101001010011111 |
3 | 1122220021210200112212220002 |
4 | 2320202010302031022133 |
5 | 3130231112112231143 |
6 | 42545320250244515 |
7 | 2446112200551224 |
oct | 270420462151237 |
9 | 48807720485802 |
10 | 12680971211423 |
11 | 4049a73724a49 |
12 | 15097a772673b |
13 | 70ca6c74c5c8 |
14 | 31ba959b394b |
15 | 16ecdb6535b8 |
hex | b8884c8d29f |
12680971211423 has 2 divisors, whose sum is σ = 12680971211424. Its totient is φ = 12680971211422.
The previous prime is 12680971211393. The next prime is 12680971211483. The reversal of 12680971211423 is 32411217908621.
It is a weak prime.
It is an emirp because it is prime and its reverse (32411217908621) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12680971211423 - 210 = 12680971210399 is a prime.
It is a super-3 number, since 3×126809712114233 (a number of 40 digits) contains 333 as substring.
It is a Sophie Germain prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12680971211483) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6340485605711 + 6340485605712.
It is an arithmetic number, because the mean of its divisors is an integer number (6340485605712).
Almost surely, 212680971211423 is an apocalyptic number.
12680971211423 is a deficient number, since it is larger than the sum of its proper divisors (1).
12680971211423 is an equidigital number, since it uses as much as digits as its factorization.
12680971211423 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 290304, while the sum is 47.
The spelling of 12680971211423 in words is "twelve trillion, six hundred eighty billion, nine hundred seventy-one million, two hundred eleven thousand, four hundred twenty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •