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12680971211423 is a prime number
BaseRepresentation
bin1011100010001000010011…
…0010001101001010011111
31122220021210200112212220002
42320202010302031022133
53130231112112231143
642545320250244515
72446112200551224
oct270420462151237
948807720485802
1012680971211423
114049a73724a49
1215097a772673b
1370ca6c74c5c8
1431ba959b394b
1516ecdb6535b8
hexb8884c8d29f

12680971211423 has 2 divisors, whose sum is σ = 12680971211424. Its totient is φ = 12680971211422.

The previous prime is 12680971211393. The next prime is 12680971211483. The reversal of 12680971211423 is 32411217908621.

It is a weak prime.

It is an emirp because it is prime and its reverse (32411217908621) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12680971211423 - 210 = 12680971210399 is a prime.

It is a super-3 number, since 3×126809712114233 (a number of 40 digits) contains 333 as substring.

It is a Sophie Germain prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12680971211483) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6340485605711 + 6340485605712.

It is an arithmetic number, because the mean of its divisors is an integer number (6340485605712).

Almost surely, 212680971211423 is an apocalyptic number.

12680971211423 is a deficient number, since it is larger than the sum of its proper divisors (1).

12680971211423 is an equidigital number, since it uses as much as digits as its factorization.

12680971211423 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 290304, while the sum is 47.

The spelling of 12680971211423 in words is "twelve trillion, six hundred eighty billion, nine hundred seventy-one million, two hundred eleven thousand, four hundred twenty-three".