Base | Representation |
---|---|
bin | 10111101001010101… |
… | …00101010111010111 |
3 | 1012202201101112020222 |
4 | 23310222211113113 |
5 | 201444323112031 |
6 | 5455404144555 |
7 | 626405332046 |
oct | 136452452727 |
9 | 35681345228 |
10 | 12694738391 |
11 | 5424937935 |
12 | 256353815b |
13 | 127408102a |
14 | 885dc655d |
15 | 4e4753e7b |
hex | 2f4aa55d7 |
12694738391 has 2 divisors, whose sum is σ = 12694738392. Its totient is φ = 12694738390.
The previous prime is 12694738319. The next prime is 12694738411. The reversal of 12694738391 is 19383749621.
Together with previous prime (12694738319) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12694738391 - 218 = 12694476247 is a prime.
It is a super-2 number, since 2×126947383912 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12694731391) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6347369195 + 6347369196.
It is an arithmetic number, because the mean of its divisors is an integer number (6347369196).
Almost surely, 212694738391 is an apocalyptic number.
12694738391 is a deficient number, since it is larger than the sum of its proper divisors (1).
12694738391 is an equidigital number, since it uses as much as digits as its factorization.
12694738391 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1959552, while the sum is 53.
The spelling of 12694738391 in words is "twelve billion, six hundred ninety-four million, seven hundred thirty-eight thousand, three hundred ninety-one".
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