12699403 has 2 divisors, whose sum is σ = 12699404. Its totient is φ = 12699402.

The previous prime is 12699397. The next prime is 12699409. The reversal of 12699403 is 30499621.

It is a balanced prime because it is at equal distance from previous prime (12699397) and next prime (12699409).

It is an emirp because it is prime and its reverse (30499621) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12699403 - 2⁵ = 12699371 is a prime.

It is a super-2 number, since 2×12699403² = 322549673112818, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (12699409) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6349701 + 6349702.

It is an arithmetic number, because the mean of its divisors is an integer number (6349702).

Almost surely, 2^12699403 is an apocalyptic number.

12699403 is a deficient number, since it is larger than the sum of its proper divisors (1).

12699403 is an equidigital number, since it uses as much as digits as its factorization.

12699403 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 11664, while the sum is 34.

The square root of 12699403 is about 3563.6221741369. The cubic root of 12699403 is about 233.3069995224.

The spelling of 12699403 in words is "twelve million, six hundred ninety-nine thousand, four hundred three".