Base | Representation |
---|---|
bin | 10010100010110110000… |
… | …001010000010101111101 |
3 | 11111211100121212220100221 |
4 | 102202312001100111331 |
5 | 131334344202231023 |
6 | 2413233525221341 |
7 | 161032634066122 |
oct | 22426601202575 |
9 | 4454317786327 |
10 | 1274364102013 |
11 | 451500349642 |
12 | 186b91b61851 |
13 | 93230c06932 |
14 | 45972992749 |
15 | 232384e385d |
hex | 128b605057d |
1274364102013 has 2 divisors, whose sum is σ = 1274364102014. Its totient is φ = 1274364102012.
The previous prime is 1274364101971. The next prime is 1274364102019. The reversal of 1274364102013 is 3102014634721.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 777109245444 + 497254856569 = 881538^2 + 705163^2 .
It is a cyclic number.
It is not a de Polignac number, because 1274364102013 - 217 = 1274363970941 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1274364102013.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1274364102019) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 637182051006 + 637182051007.
It is an arithmetic number, because the mean of its divisors is an integer number (637182051007).
Almost surely, 21274364102013 is an apocalyptic number.
It is an amenable number.
1274364102013 is a deficient number, since it is larger than the sum of its proper divisors (1).
1274364102013 is an equidigital number, since it uses as much as digits as its factorization.
1274364102013 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24192, while the sum is 34.
Adding to 1274364102013 its reverse (3102014634721), we get a palindrome (4376378736734).
The spelling of 1274364102013 in words is "one trillion, two hundred seventy-four billion, three hundred sixty-four million, one hundred two thousand, thirteen".
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