Search a number
-
+
12750276514951 is a prime number
BaseRepresentation
bin1011100110001010011110…
…1100111101010010000111
31200010220200200201002100201
42321202213230331102013
53132400031241434301
643041221323351331
72454114511115563
oct271424754752207
950126620632321
1012750276514951
1140763a876a2a8
12151b109982547
13716465c93851
1432118c2326a3
151719e5c8d201
hexb98a7b3d487

12750276514951 has 2 divisors, whose sum is σ = 12750276514952. Its totient is φ = 12750276514950.

The previous prime is 12750276514949. The next prime is 12750276514957. The reversal of 12750276514951 is 15941567205721.

It is a weak prime.

It is an emirp because it is prime and its reverse (15941567205721) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12750276514951 - 21 = 12750276514949 is a prime.

It is a super-2 number, since 2×127502765149512 (a number of 27 digits) contains 22 as substring.

Together with 12750276514949, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 12750276514892 and 12750276514901.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12750276514957) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6375138257475 + 6375138257476.

It is an arithmetic number, because the mean of its divisors is an integer number (6375138257476).

Almost surely, 212750276514951 is an apocalyptic number.

12750276514951 is a deficient number, since it is larger than the sum of its proper divisors (1).

12750276514951 is an equidigital number, since it uses as much as digits as its factorization.

12750276514951 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5292000, while the sum is 55.

The spelling of 12750276514951 in words is "twelve trillion, seven hundred fifty billion, two hundred seventy-six million, five hundred fourteen thousand, nine hundred fifty-one".